Equivalently, \[\mathbf K \mathbf u = \omega^2 \mathbf M \mathbf u\]

If \( \mathbf A \mathbf v = \lambda \mathbf v\) then
\(\lambda\) is an *eigenvalue* of \(\mathbf A\) and
\(\mathbf v\) is the corresponding *eigenvector*.

The generalized eigenvalue problem is \( \mathbf A \mathbf v = \lambda \mathbf B \mathbf v\).

The generalized eigenvalue problem is \( \mathbf A \mathbf v = \lambda \mathbf B \mathbf v\).

This is a generalized eigenvalue/eigenvector problem.

R. Funnell Last modified: 2018-11-07 12:52:06

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